<=> \(\dfrac{7}{12}-\dfrac{4}{2}=-\dfrac{11}{12}\)
\(=\dfrac{7}{12}-\dfrac{27}{7}\times\dfrac{7}{18}=\dfrac{7}{12}-\dfrac{27}{18}=\dfrac{7}{12}-\dfrac{3}{2}=-\dfrac{11}{12}\)
<=> \(\dfrac{7}{12}-\dfrac{4}{2}=-\dfrac{11}{12}\)
\(=\dfrac{7}{12}-\dfrac{27}{7}\times\dfrac{7}{18}=\dfrac{7}{12}-\dfrac{27}{18}=\dfrac{7}{12}-\dfrac{3}{2}=-\dfrac{11}{12}\)
D=√147 +√54 -4√27
A =√112 - 7√(1/7) - 14√(1/28)-21/√7
B = 3√2(4 -√2) + 3(1 - 2√2)^2
C = 2√27 + 5√12 - 3√48
E = (√15 - 2√3)^2 + 12√5
F = 3√50 - 7√8 + 12√18
G = 2√80 - 2√245 + 2√180
H =√28 - 4√63 + 7√112
I =√44 -√176 + 2√275
D=√147 +√54 -4√27
A =√112 - 7√(1/7) - 14√(1/28)-21/√7
B = 3√2(4 -√2) + 3(1 - 2√2)^2
C = 2√27 + 5√12 - 3√48
E = (√15 - 2√3)^2 + 12√5
F = 3√50 - 7√8 + 12√18
G = 2√80 - 2√245 + 2√180
H =√28 - 4√63 + 7√112
I =√44 -√176 + 2√275
rút gọn
a)3 √5 + √20-2 √5
b)2 √2+ √8+ √50
c) 4√3+ √ 27 -√45 +2 √5
d) √ 75+ √ 48- √300
e)( √28- √12- √7) √7 +2 √21
f)( √99- √18- √11) √11+3 √22
g)3 √45-5 √125x +7 √20x+28(x>=0)
Giải phương trình: \(5\sqrt{\frac{9x-27}{25}}-7\sqrt{\frac{4x-12}{9}}-7\sqrt{x^2-9}+18\sqrt{\frac{9x^2-81}{91}}=0\)
tính
A=\(\left(1-\sqrt{7}\right).\dfrac{\sqrt{7}+7}{2\sqrt{7}}\)
B=\(3\sqrt{3}+4\sqrt{12}-5\sqrt{27}\)
C=\(\sqrt{32}-\sqrt{50}+\sqrt{18}\)
D=\(\sqrt{72}+\sqrt{4\dfrac{1}{2}}-\sqrt{32}-\sqrt{162}\)
E=\(\dfrac{1}{2}\sqrt{48}-2\sqrt{75}-\dfrac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\dfrac{1}{3}}\)
\(\sqrt{11+2\sqrt{18}}\)
\(\sqrt{7+2\sqrt{10}}\)
\(\sqrt{7+4\sqrt{3}}\)
\(\sqrt{12-2\sqrt{55}}\)
Tính:
A/ √(27-12√5)
B/ √(13+4√10)
C/ √8-3√32+√72
D/ 6√1√20-2√27+√125
E/ √(4-√7)-√(4-7)+√2
Rút gọn: (Giải chi tiết từng bước)
7) \(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
8) \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
Tính :
a) (\(\sqrt{12}+\sqrt{75}+\sqrt{27}\)) / \(\sqrt{15}\)
b) \(\frac{\left(12\sqrt{50}-8\sqrt{200}+7\sqrt{450}\right)}{\sqrt{10}}\)
c)\(\frac{\left(\sqrt{\frac{1}{7}}-\sqrt{\frac{16}{7}}+\sqrt{\frac{9}{7}}\right)}{7}\)