\(x^3+8y^3=x^3+\left(2y\right)^3=\left(x+2y\right)\left[x^2-x.2y+\left(2y\right)^2\right]=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)\(a^6-b^3=\left(a^2\right)^3-b^3=\left(a^2-b\right)\left[\left(a^2\right)^2+a^2.b+b^2\right]=\left(a^2-b\right)\left(a^4+a^2b+b^2\right)\)
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