\(\Leftrightarrow6x\left(x-3\right)-4\left(x-3\right)=0\Leftrightarrow2\left(x-3\right)\left(3x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{2}{3}\end{matrix}\right.\)
tìm x biet;
1) x2 - 2x + 4x -8 = 0
2) x(x+3)-3x -9 =0
3) x2 - 6x + 5 = 0
các ban giai giup minh nha
ai giup minh vs
tim x biet
(3x+2)(2x+9)-(x+2)(6x+1)=x+1-(x-9)
tim x,y,z biết
a)(2x-3)^2=0
b) 25x^2-10x+1=0
c) 6x+9=-x^2
d) 169-y^2=0
e) 2x^2-2xy-4x+5=0
giup mik vs
tôi đi hok
nhanh nhé
Tìm x, biết:
a. 4x2-4x=-1
b. 8x3+12x2+6x+1=0
có ai lm giúp mk vs kg?
Tim x
(2x - 5)2 - (x-2).(4x+1) = 0
Cac ban giup minh vs nhe
chung minh bieu thuc sau ko phu thuoc vao x ( 2x + 3) (4x^2 - 6x + 9 ) - 2 ( 4x^3 - 1 )
giai nhanh giup minh voi minh voi
ai giup minh voi
a) x(x+1)(x+2)(x+3)=24
b)5x(2-3x)=4-6x
c) (5-x)(2+3x)=4-9x2
d) 25-x2=4x(5+x)
Tìm x
x^2 - 4x - 12 = 0
4x^2 + 4x - 24 = 0
8x^3 - 12x^2 + 6x - 1 = 0
(2x -3)(6x-1)(4x-5) = 0
Tìm x.
Ai thích coi anime kb face book vs mình nhé,
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