\(6\left(x+7\right)+2\left(x+11\right)-5x=83\)
\(\Leftrightarrow42+6x+22+2x-5x=83\)
\(\Leftrightarrow6x+2x-5x+\left(42+22\right)=83\)
\(\Leftrightarrow3x+64=83\)
\(\Leftrightarrow3x=83-64\)
\(\Leftrightarrow3x=19\)
\(\Leftrightarrow x=\frac{19}{3}\)
Vậy ...........