Question

5/x+y/4+1/8.Tìm x,y(x,y là số nguyên)

 

Answer 1

\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\Leftrightarrow\frac{20}{4x}+\frac{xy}{4x}=\frac{1}{8}\)

\(\Leftrightarrow\frac{20+xy}{4x}=\frac{1}{8}\)\(\Leftrightarrow8\left(20+xy\right)=4x\)

\(\Leftrightarrow2\left(20+xy\right)=x\)\(\Leftrightarrow40+2xy=x\)

\(\Leftrightarrow40+2xy-x=0\)

\(\Leftrightarrow x\left(2y-1\right)=-40\)

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