Ta có: 5x = 8y = 20z
\(\Rightarrow\frac{x}{8}=\frac{y}{5};\frac{y}{20}=\frac{z}{8}\)
\(\Rightarrow\frac{x}{48}=\frac{y}{20}=\frac{z}{8}=\frac{x-y-z}{48-20-8}=\frac{20}{20}=1\)
Vậy x = 1 x 48 = 48
y = 1 x 20 = 20
z = 1 x 8 = 8
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Thử lại: 48 - 20 - 8 = 20
\(5x=8y=20z\Rightarrow\)\(\frac{5x}{40}=\frac{8y}{40}=\frac{20z}{40}\Rightarrow\frac{x}{8}=\frac{y}{5}=\frac{z}{2}=\frac{x-y-z}{8-5-2}=20\)
suy ra \(x=20\times8=160\)
\(y=20\times5=10\)
\(z=20\times2=40\)