Question

(5x-4)²-49x²=0

Answer 1

\(\Leftrightarrow\left(5x-4-7x\right)\left(5x-4+7x\right)=0\\ \Leftrightarrow\left(-2x-4\right)\left(12x-4\right)=0\\ \Leftrightarrow\left(x+2\right)\left(3x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x=\dfrac{1}{3}\end{matrix}\right.\)

Answer 2

⇔(5x-4-49x)(5x-4+49x)=0

⇔(-44x-4)(54x-4)=0

⇒-44x-4=0 hoặc 54x-4=0

TH1:-44x-4=0                TH2:54x-4=0

     ⇔x=-1/11                   ⇔x=2/27

Vậy xϵ{-1/11;2/27}

Answer 3

(5x-4-7x)(5x-4+7x)=0

(-2x-4)(12x-4)=0

⇒-2x-4=0 hoặc 12x-4=0

    x=-2                  x=1/3

 

Answer 4

x⁵-x⁴+x³-x²
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