Question

(5\(\sqrt{7}\)+ 7\(\sqrt{5}\)) / \(\sqrt{35}\)

xin mn giup em vs ak

Answer 1

\(\frac{\left(5\sqrt{7}+7\sqrt{5}\right)}{\sqrt{35}}\)

= \(\frac{\sqrt{5}.\left(\sqrt{35}+7\right)}{\sqrt{35}}\)

= \(\frac{\sqrt{35}+7}{\sqrt{7}}\)

= \(\sqrt{5}+\sqrt{7}\)

Answer 2

\(\frac{5\sqrt{7}+7\sqrt{5}}{\sqrt{35}}=\frac{\sqrt{5}.\sqrt{5}.\sqrt{7}+\sqrt{7}.\sqrt{7}.\sqrt{5}}{\sqrt{35}}.\)

\(=\frac{\sqrt{5}.\sqrt{35}+\sqrt{7}.\sqrt{35}}{\sqrt{35}}\)

\(=\frac{\sqrt{35}\left(\sqrt{5}+\sqrt{7}\right)}{\sqrt{35}}=\sqrt{5}+\sqrt{7}\)

Answer 3

(2\(\sqrt{8}\)-3\(\sqrt{3}\)+ 1) / \(\sqrt{6}\)

Answer 4

\(\frac{5\sqrt{7}+7\sqrt{5}}{\sqrt{35}}=\frac{\sqrt{5}.\sqrt{5}.\sqrt{7}+\sqrt{7}.\sqrt{7}.\sqrt{5}}{\sqrt{35}}\)

\(\frac{\sqrt{35.}\sqrt{7}+\sqrt{35}.\sqrt{5}}{\sqrt{35}}\)

\(=\frac{\sqrt{35}.\left(\sqrt{5}+\sqrt{7}\right)}{\sqrt{35}}\)

\(=\sqrt{5}+\sqrt{7}\)