\(5\left(x-3\right)-4=2\left(x-1\right)\)
\(\Leftrightarrow5x-15-4=2x-2\)
\(\Leftrightarrow3x=17\)
\(\Leftrightarrow x=\dfrac{17}{3}\)
\(5\left(x-3\right)-4=2\left(x-1\right)\)
\(5x-15-4=2x-2\\ \text{⇔}5x-2x=15+4-2\\\text{⇔} 3x=17\\ \text{⇔}x=\dfrac{17}{3}\)
\(5\left(x-3\right)-4=2\left(x-1\right)\)
\(\Leftrightarrow5x-15-4-2x+2=0\)
\(\Leftrightarrow3x-17=0\)
\(\Leftrightarrow x=\dfrac{17}{3}\)