Question

4(x-5)-(3x-1)=x-19

Answer 1

4(x−5)−(3x−1)=x−194(x−5)−(3x−1)=x−19

⇒4x−20−3x+1=x−19⇒4x−20−3x+1=x−19

⇒4x−3x−x=−19+20−1⇒4x−3x−x=−19+20−1

⇒0x=0⇒0x=0

⇒x∈R⇒x∈R

Chúc bạn học tốt nhé! ^^

Answer 2

4(x−5)−(3x−1)=x−19

⇒4x−20−3x+1=x−19

⇒4x−3x−x=−19+20−1

⇒0x=0

⇒x∈R

Chúc bạn học tốt nhé! ^^