Question

4(x-3)^2-(2x-1)(2x+5)=10+x

Answer 1

\(4\left(x-3\right)^2-\left(2x-1\right)\left(2x+5\right)=10+x\\ \Rightarrow4\left(x^2-6x+9\right)-\left(4x^2-2x+10x-5\right)=10+x\\ \Rightarrow4x^2-24x+36-4x^2-8x+5-10-x=0\\ \Rightarrow-33x+31=0\\ \Rightarrow x=\dfrac{31}{33}\)