\(\dfrac{4}{3}-\dfrac{3}{5}=\dfrac{20}{15}-\dfrac{9}{15}=\dfrac{11}{15}\)
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\(\dfrac{4}{3}=\dfrac{4\times5}{3\times5}=\dfrac{20}{15};\dfrac{3}{5}=\dfrac{3\times3}{5\times3}=\dfrac{9}{15}\)
\(\dfrac{20}{15}-\dfrac{9}{15}=\dfrac{11}{15}\)
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\(\dfrac{4}{3}\)-\(\dfrac{3}{5}\)=\(\dfrac{20}{15}\)-\(\dfrac{9}{15}\)
=\(\dfrac{20-9}{15}\)
= \(\dfrac{11}{15}\)
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