thanh tịnh sai rồi câu này = \(\frac{-20}{39}\)
=-4/15-4/35-4/63-4/99-4/143
=-8/21-4/63-4/99-4/143
=-4/9-4/99-4/143
=-20/39
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thanh tịnh sai rồi câu này = \(\frac{-20}{39}\)
=-4/15-4/35-4/63-4/99-4/143
=-8/21-4/63-4/99-4/143
=-4/9-4/99-4/143
=-20/39
B = 1/4 + 1/15 + 1/35 + 1/63 + 1/99 + 1/143 + 1/195
Tính hợp lí : \(B=\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
1/3 - 2/5 +3/35 - 4/63 + 5/99 - 6/143
cho A va B biet:
\(A=\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\) va \(B=\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
A=\(\dfrac{2}{3}\)+\(\dfrac{14}{15}\)+\(\dfrac{34}{35}\)+\(\dfrac{62}{63}\)+\(\dfrac{98}{99}\)+\(\dfrac{142}{143}\)+\(\dfrac{194}{195}\)
Và B=5+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^3}\)+\(^{\dfrac{1}{4^4}}\)+\(\dfrac{1}{5^5}\)+\(\dfrac{1}{6^6}\)+\(\dfrac{1}{7^7}\).So sánh A và B
A = \(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)va B = \(\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
So sánh
a,0,25.1+3/5.(5/4)2:4/7
b,1/15+1/35+1/63+1/99+1/143+1/195
c,1-(5+3/8+x-7+5/24):(-16+2/3)=0
So sánh A và B biết:
\(A=\frac{21^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}};B=\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
Bài 1 :So sánh
A= 2^19 .27^3+15.4^9.9^4/6^9.2^10+12^10 va B = 4/35+4/63+4/99+4/143+4/195
Bài 2 : tìm x biết :
60%.x+0,4.x +x:3=2