Ta có: \(4\frac{3}{5}:\frac{2}{3}+1\frac{1}{5}:\frac{2}{5}\)
\(=\frac{12}{5}.\frac{3}{2}+\frac{6}{5}.\frac{5}{2}\)
\(=\frac{18}{5}+3\)
\(=6,6\)
Vậy..........
\(4\frac{3}{5}:\frac{2}{3}+1\frac{1}{5}:\frac{2}{5}\)
= \(\frac{23}{5}:\frac{2}{3}+\frac{6}{5}:\frac{2}{5}\)
= \(\frac{23}{5}x\frac{3}{2}+\frac{6}{5}x\frac{5}{2}\)
= \(\frac{69}{10}+\frac{30}{10}\)
\(=\frac{99}{10}\)