a) \(n_{C_{12}H_{22}O_{11}}=\dfrac{25,65}{364}=0,07\left(mol\right)\)
b) \(n_{Cl_2}=\dfrac{1,2.10^{23}}{6.10^{23}}=0,2\left(mol\right)\)
\(m_{Cl_2}=0,2.71=14,2\left(g\right)\)
c) \(n_{C_2H_2}=\dfrac{52}{26}=2\left(mol\right)\)
\(m_{C_2H_2}=2.22,4=44,8\left(l\right)\)
d) \(n_{O_2}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\)
Số phân tử của O2 là 0,25.6.1023 = 1,5.1023