3y + x = x : y = 5 . ( x + y )
Ta có :
3y + x = 5 . ( x + y )
3y + x = 5x + 5y
3y - 5y = 5x - x
-2y = 4x
\(\frac{x}{y}=\frac{-2}{4}=\frac{-1}{2}\)
\(\Rightarrow5.\left(x+y\right)=\frac{-1}{2}\)
\(\Rightarrow x+y=\frac{-1}{10}\)
Mà 3y + x = \(\frac{-1}{2}\)
2y + ( y + x ) = \(\frac{-1}{2}\)
2y + \(\frac{-1}{10}=\frac{-1}{2}\)
\(2y=\frac{-1}{2}-\frac{-1}{10}\)
\(2y=\frac{-2}{5}\)
\(y=\frac{-2}{5}:2=\frac{-1}{5}\)
\(\Rightarrow x=\frac{-1}{10}-\frac{-1}{5}=\frac{1}{10}\)
Vậy x = \(\frac{1}{10}\); y = \(\frac{-1}{5}\)