Question

\(3^x+3^{x+1}+3^{x+2}=117\)

Answer 1

=> 3^x . (1+3+3^2) = 117

=> 3^x . 13 = 117

=> 3^x = 117 : 13 = 9

=> 3^x = 3^2

=> x = 2

Vậy x = 2

Tk mk nha

Answer 2

3^x + 3^x+1 +3^x+2 = 117

=> 3^x + 3^x . 3 + 3^x . 9 = 117

=> 3^x ( 1 + 3 + 9) = 117

=> 3^x . 13 = 117

=> 3^x = 9

=> x = 2

Answer 3

\(3^x+3^{x+1}+3^{x+2}=117\Leftrightarrow3^x+3\cdot3^x+3^2\cdot3^x=117\)

\(\Leftrightarrow3^x\cdot\left(1+3+3^2\right)=117\Leftrightarrow3^x\cdot13=117\)

\(\Leftrightarrow3^x=9\Leftrightarrow3^x=3^2\Leftrightarrow x=2\)

Vậy x = 2

Tích cho mk nhoa !!!! ~~

Answer 4

3^x (1+3+9)=117

\(\Leftrightarrow\)3^x=9=3²

\(\Leftrightarrow\)x=2

vậy x=2