\(3x+2x^2-2=0\\ \Rightarrow\left(2x^2+4x\right)-\left(x+2\right)=0\\ \Rightarrow2x\left(x+2\right)-\left(x+2\right)=0\\ \Rightarrow\left(2x-1\right)\left(x+2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-2\end{matrix}\right.\)
⇔2x2+4x-x-2=0
⇔2x(x+2)-(x+2)=0
⇔(x+2)(2x-1)=0
⇔x+2=0 hoặc 2x-1=0
⇔x=-2 hoặc x=1/2