Phân tích \(x^3+1\) thành nhân tử nha bạn =))
Rồi \(3x^2+6=3\left(x^2+2\right)\)đến đây bạn có thể tự làm =))
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L2
26 tháng 10 2021 lúc 9:41
6) \(\sqrt{x^2+12x+36}=-x-6\)
7) \(\sqrt{9x^2-12x+4}=3x-2\)
8) \(\sqrt{16-24x+9x^2}=2x-10\)
9) \(\sqrt{x^2-6x+9}==2x-3\)
10) \(\sqrt{x^2-3x+\dfrac{9}{4}}=\dfrac{3}{x}x-4\)
a)\(\sqrt{9\left(2-3x\right)^2}=6\)
b)\(\sqrt{4x^2-9}=2\sqrt{2x+3}\)
c)\(\sqrt{10\left(x-3\right)}=\sqrt{20}\)
d)\(\sqrt{x^2+6x+9}=3x-6\)
Giải phương trình:
a)\(6\sqrt{x+8}=16+3x-x^2\)
b)\(\sqrt{3x+1}-\sqrt{x+3}+7x^2-7=0\)
c) \(6\left(x+\frac{1}{x}\right)+2=7\sqrt{x+3}\)
d) \(3x+10=\frac{1}{x}+4\sqrt{6x+3}\)
1) x+1+sqrt{x^2-4x+1}3sqrt{x}2) 4x^3+x-left(x+1right)sqrt{2x+1}03) x-sqrt{x}1-sqrt{2left(x^2-x+1right)}4) sqrt{x+1}+sqrt{4-x}+sqrt{left(x+1right)left(4-xright)}55) sqrt{3x-2}+sqrt{x-1}4x-9+2sqrt{3x^2-5x+2}6) 3sqrt{x+2}-6sqrt{2-x}+4sqrt{4-x^2}10-3x
Đọc tiếp
1) \(x+1+\sqrt{x^2-4x+1}=3\sqrt{x}\)
2) \(4x^3+x-\left(x+1\right)\sqrt{2x+1}=0\)
3) \(x-\sqrt{x}=1-\sqrt{2\left(x^2-x+1\right)}\)
4) \(\sqrt{x+1}+\sqrt{4-x}+\sqrt{\left(x+1\right)\left(4-x\right)}=5\)
5) \(\sqrt{3x-2}+\sqrt{x-1}=4x-9+2\sqrt{3x^2-5x+2}\)
6) \(3\sqrt{x+2}-6\sqrt{2-x}+4\sqrt{4-x^2}=10-3x\)
Giair phương trình: \(\left(x+2\right)\sqrt{3x+6}-2\sqrt{x^2+x-1}+3x^2-10=0\)
H24
20 tháng 8 2021 lúc 14:43
giải phương trình sau:
a) \(4x^2+\left(8x-4\right).\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
b) \(8x^3-36x^2+\left(1-3x\right)\sqrt{3x-2}-3\sqrt{3x-2}+63x-32=0\)
c) \(2\sqrt[3]{3x-2}-3\sqrt{6-5x}+16=0\)
d) \(\sqrt[3]{x+6}-2\sqrt{x-1}=4-x^2\)
Phương pháp 6. Biến đổi về dạng \(A^2=B^2\)
a \(x^2+4\sqrt{x+3}=3x+6\)
b \(4x^2+14x+11=4\sqrt{6x+10}\)
c \(4\sqrt{x+1}=x^2-5x+14\)
Tím x:
1) \(\sqrt{10+\sqrt{3x}}=2+\sqrt{6}\)
2) \(\sqrt{4x+20}-3\sqrt{5+x}+\frac{4}{3}\sqrt{9x+45}=6\)
Rút gọn:
a/ \(\left(\frac{x^2}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{x+1}\right):\left(x-2+\frac{10-x^2}{x+2}\right)\)
b/\(\frac{\sqrt{6+2\left(\sqrt{6}+\sqrt{3}+\sqrt{2}\right)}-\sqrt{6-2\left(\sqrt{6}-\sqrt{3}+\sqrt{2}\right)}}{\sqrt{2}}\)
\(\left(5\right)\sqrt{x+3-4\sqrt{x-1}}\sqrt{x+8+6\sqrt{x-1}}=5\)
\(\left(6\right)2x^2+3x+\sqrt{2x^2+3x+9}=33\)
\(\left(7\right)\sqrt{3x^2+6x+12}+\sqrt{5x^4-10x^2+30}=8\)
\(\left(8\right)x+y+z+8=2\sqrt{x-1}+4\sqrt{y-2}+6\sqrt{z-3}\)