\(3x^2-x=0\)
\(\Leftrightarrow x\left(3x-1\right)=0\)
=> x=0 hoặc 3x-1=0
3x=1
x=\(\dfrac{1}{3}\)
Vậy........
\(3x^2-x=0\)
\(\Leftrightarrow x\left(3x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\3x-1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\3x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\end{matrix}\right.\)
Vậy \(S=\left\{0;\dfrac{1}{3}\right\}\)
3x2 - x= 0
x.(3x - 1)= 0 => x = 0 hoặc 3x - 1 = 0
nếu 3x - 1 = 0
3x = 1
=> x = 1/3
vậy x = 0 hoặc x = 1/3