đk : x khác -2 ; -1/2
\(\Rightarrow6x+3=5x+10\Leftrightarrow x=7\left(tmđk\right)\)
ĐKXĐ:\(x\ne-2,x\ne-\dfrac{1}{2}\)
\(\dfrac{3}{x+2}=\dfrac{5}{2x+1}\\ \Leftrightarrow3\left(2x+1\right)=5\left(x+2\right)\\ \Leftrightarrow6x+3=5x+10\\ \Leftrightarrow x=7\left(tm\right)\)
\(\Rightarrow3\cdot\left(2x+1\right)=\left(x+2\right)\cdot5\\ \Rightarrow6x+3=5x+10\\ \Rightarrow6x-5x=10-3\\ \Rightarrow x=7\)