Question

(3x-4)(x-2)=3x(x-9)-3

Tìm x

Answer 1

(3x-4).(x-2)=3x(x-9)-3

<=> 3x^2-6x-4x+8=3x^2-27x-3

<=> 3x^2-6x-4x+8-3x^2+27x+3=0

<=> 17x+11=0

=> 17x=-11 => x=-11/17

Answer 2

\(\left(3x-4\right)\left(x-2\right)=3x\left(x-9\right)-3\)

\(< =>3x\left(x-2\right)-4\left(x-2\right)=3x\left(x-9\right)-3\)

\(< =>3x^2-10x+8=3x^2-27x-3\)

\(< =>3x^2-10x+8-3x^2+27x+3=0\)

\(< =>17x+11=0< =>17x=-11< =>x=-\frac{11}{17}\)