Question

3x(-4/3x+1)-4x(x-2)=10

Answer 1

3\(x\)(- \(\dfrac{4}{3}\)\(x\) + 1) - 4\(x\).(\(x\) - 2) = 10

-4\(x^2\) + 3\(x\) - 4\(x^2\) + 3\(x\) + 8\(x\) = 10

-8\(x^2\) + 14\(x\) - 10 = 0

4\(x^2\) + 7\(x\) - 5 = 0

4.(\(x^2\) + 2.\(\dfrac{7}{8}\) + \(\dfrac{49}{64}\)) - \(\dfrac{129}{16}\) = 0

4.(\(x\) + \(\dfrac{7}{8}\))²  = \(\dfrac{129}{16}\)

   (\(x\) + \(\dfrac{7}{8}\))² =  \(\dfrac{129}{16}\)

    \(x\)           = \(\dfrac{\pm\sqrt{129}-7}{8}\)