\(\frac{\left(3x-1\right)^2}{2}=\frac{-4}{3x-1}\)
\(\Rightarrow\left(3x-1\right)^3=-8=\left(-2\right)^3\)
\(\Rightarrow3x-1=-2\)
\(\Rightarrow3x=-1\)
\(\Rightarrow x=\frac{-1}{3}\)
Tìm nghiệm : a) (2x-3).(2x+3) B)(x-4).(x-1).(x-2) C)2x(3x-1)-3x(5+2x) D)(3x-2).(3x+2)-4.(x-1)
Bài 2 Tìm x biết 1, (2x-2).(3x+1)-(3x-2).(2x-3)=5 2,(1-3x).(3x-5)-(2x-4)(2-3x)=x-6 3,(2x-1).(4x^2+2x+1)-(2x+1)(4x^2-2x+1)=5x+6 Giúp tớ với
1) Tìm x,biết :
a) 3/2 . |x-5/3| - 4/5 = 4/3 . |x-5/3| + 1
b) 2.|3x +1| = 1/3 . |3x + 1| +5
c) 1/4 - 5/2 . | 3x - 1/5| = 2/3. |3x - 1/5| - 2/3
b1:
[4+2x]=-3x [3x-1]+2=x
[x+15]+1=3x [2x-5]+x=2
b2:
[2x-5]=x+1 [3x-2]-1=x
[3x-7]=2x+1 [2x-1]+1=x
(3/4x+5)+(2/3x-4)-(1/6x+1)=(1/3x+4)-(1/3x-3)
tìm x:|5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x: 5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x: 5(3x+1)|+|2(3x+1)|+|3x+1|=4
tìm x:|5(3x+1)|+|2(3x+1)|+|3x+1|=4
*Dạng 2: Đa thức BT1: Thực hiện phép tính a) 3x(x^2-5x+7) b) (x+4)(-x^2+6x+5) c) (3x-1)(3x+5)-7(x^2+2) d) (-5x^5 + 2x^4 - 1/3x^3): (-1/2x^3)