\(\left(3n+1\right)⋮\left(11-2n\right)\Rightarrow2\left(3n+1\right)=6n+2=6n-33+35=3\left(2n-11\right)+35⋮\left(11-2n\right)\)
\(\Leftrightarrow35⋮\left(11-2n\right)\Leftrightarrow2n-11\inƯ\left(35\right)=\left\{-35,-7,-5,-1,1,5,7,35\right\}\)
\(\Leftrightarrow n\in\left\{-12,2,3,5,6,8,23\right\}\)
Thử lại đều thỏa mãn.