từ phần sau số 0 thứ nhất là câu mới nha
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\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\left(2x+\frac{3}{5}\right)^{^2}-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)+\frac{1}{9}=0\)
Tìm x
\(\left(2x+\frac{3}{5}\right)^2-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
giải nhanh hộ mình với, mai mình nộp rồi
\(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
1) frac{2}{5}xfrac{1}{3}-frac{2}{15}:frac{1}{5}+frac{3}{5}xfrac{1}{3}2)left(3frac{1}{3}+2,5right):left(3frac{1}{6}-4frac{1}{5}right)-frac{11}{31}3)left[6+left(frac{1}{2}right)^3-left|-frac{1}{2}right|right]:frac{3}{12}4)frac{18}{37}+frac{8}{24}+frac{19}{37}-1frac{23}{24}+frac{2}{3}5)left(-2right)^3xleft(frac{3}{4}-0,25right):left(2frac{1}{4}-1frac{1}{6}right)6)left(frac{2}{5}right)^2+5frac{1}{2}xleft(45-2right)+frac{23}{4}7)frac{4}{9}-19frac{1}{3}-frac{4}{9}x39frac{1}{3}8)left(-frac{1}{2}right)^...
Đọc tiếp
1) \(\frac{2}{5}x\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}x\frac{1}{3}\)
2)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)
3)\(\left[6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right]:\frac{3}{12}\)
4)\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)
5)\(\left(-2\right)^3x\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
6)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}x\left(45-2\right)+\frac{23}{4}\)
7)\(\frac{4}{9}-19\frac{1}{3}-\frac{4}{9}x39\frac{1}{3}\)
8)\(\left(-\frac{1}{2}\right)^2:\frac{1}{4}-2x\left(-\frac{1}{2}\right)^2\)
9)\(125\%x\left(-\frac{1}{2}\right)^3:\left(1\frac{5}{16}-1,5\right)+2008^0\)
giúp mình nha mai mình học rùi
\(9.\left(\frac{-1}{3}\right)^3x-3.\left(\frac{-1}{3}\right)^2x+\left(\frac{-1}{3}\right)x+1=0\)
tìm x
a) left|2xfrac{1}{3}right|+frac{5}{6}1b)frac{17}{2}-left|2x-frac{3}{4}right|-frac{7}{4}c) frac{2}{3}x-frac{3}{2}xfrac{5}{12}d) frac{2}{5}+frac{3}{5}.left(3x-3,7right)-frac{53}{10}e) frac{7}{9}:left(2+frac{3}{4}xright)+frac{5}{9}frac{23}{27}f) left(2frac{4}{5}x-50right):frac{2}{3}51g)left(x+frac{1}{2}right).left(frac{2}{3}-2xright)0h)x.3frac{1}{4}+left(-frac{7}{6}right).x-1frac{2}{3}frac{5}{12}i)frac{6}{2}frac{-5+x}{15}k)frac{1}{21}+frac{1}{28}+frac{1}{36}+...+frac{2}{xleft(x+1right)}frac{2}{9}
Đọc tiếp
a) \(\left|2x\frac{1}{3}\right|+\frac{5}{6}=1\)
b)\(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
c) \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
d) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=-\frac{53}{10}\)
e) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
f) \(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
g)\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
h)\(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
i)\(\frac{6}{2}=\frac{-5+x}{15}\)
k)\(\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+...+\frac{2}{x\left(x+1\right)}=\frac{2}{9}\)
a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)0
b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)
c) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)
Tìm x và y
a, \(\left|3x-\frac{1}{2}\right|+\left|\frac{1}{2}y+\frac{3}{5}\right|=0\)
b,\(\left|\frac{3}{2}x+\frac{1}{9}\right|+\left|\frac{1}{5}y-\frac{1}{2}\right|\)\(\le\)\(0\)
Tìm x, biết:2|frac{1}{2}x-frac{1}{3}|-frac{3}{2}frac{1}{4} left(x+frac{1}{5}right)^2+frac{17}{25}frac{26}{25} 3left(x-frac{1}{2}right)-5left(x+frac{3}{5}right)-x+frac{1}{5}3(3x-frac{1}{2})^3+frac{1}{9}0 frac{3}{4}-2.|2x-frac{2}{3}|2 frac{2}{3}x-frac{1}{2}xfrac{5}{12}Help me, please
Đọc tiếp
Tìm x, biết:
\(2|\frac{1}{2}x-\frac{1}{3}|-\frac{3}{2}=\frac{1}{4}\) \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\) \(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(3(3x-\frac{1}{2})^3+\frac{1}{9}=0\) \(\frac{3}{4}-2.|2x-\frac{2}{3}|=2\) \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
Help me, please