Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
\(=3\cdot2^3\cdot5^2+2\cdot2^6\cdot2^2\cdot3+2^3\cdot2\cdot3\cdot2^2+3\cdot2\cdot3\cdot2^2\\ =2^3\cdot3\cdot5^2+2^9\cdot3+2^6\cdot3+2^3\cdot3^2\\ =2^3\cdot3\left(5^2+2^6+2^3+3\right)=24\left(25+64+8+3\right)\\ =24\cdot100=2400\)
\(3.8.5^2+2.4^3.12+\left(2^3+3\right).6.4\)
\(600:\left\{450-\left[450-\left(2^3.5^2\right)\right]\right\}\)
Bài 1: Tính. ( Nhanh nếu có thể )
a) \(25.8^3-23.8^3\)
b) \(5^4-2.5^3\)
c) \(2.4^3-4^3.7-6.4^3\)
d) \(3^2.10^3-\left[13^2-\left(5^2.4+2^2.15\right)\right].10^3\)
Tính hợp lí : \(4.24.5^2-\left(3^3.18+3^3.12\right)\)
Rút gọn:
\(\dfrac{\left(-2\right)^3.9^3.5^5.7.8}{3^6.4^4.25^3.14}\)
\(^{3^2.10^3-\left[13^2-\left(5^2.4+2^2.15\right)\right].10^3}\)
A=\(^{3^2.10^2-\left[13^2-\left(5^2.4+2^2.15\right)\right].10^3}\)
thực hiện phép tính
\(a=\left[\left(3^2.5^2.4^3\right):\left(2^3.3^2\right)\right].2005^0\)
1)CMR
B= 3+3 ^ 3 + 3^5 +...+ 3^1991 chia hết cho 13
C= 3+ 3^3 + 3^5 +3^7 +... + 3^2n-1 chia hết cho 30
2)Cmr
1.4.+2.4^2 + 2. 4^3+4.4^4+5.4^5+6.4^6 chia hết cho 3
tinh:
\(3+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{100}}\)
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
trinh bay cach lam nua nhe
