Ta có \(\left(3^5.3^7\right):3^{10}+5.2^4-7^3:7\)
\(=3^{5+7}:3^{10}+5.16-7^{3-1}\)
\(=3^{12}:3^{10}+80-7^2\)
\(=3^2+80-49\)
\(=9+80-49\)
\(=40\)
( 3^5 . 3^7 ) : 3^10 + 5 . 2^4 - 7^3 : 7
= 3^12 : 3^10 + 5 . 16 - 7^2
= 3^2 + 80 - 14
= 9 + 80 - 14
= 75
=3^12 :3^10+5+16-7^3:7
=3^2 +21 +7^2
=9+21+49
=79
(35 . 37 ) : 310 + 5 . 24 - 73 : 7
= 9 + 31
= 40
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