\(\dfrac{3}{4}-\dfrac{5}{6}< \dfrac{x}{12}< 1-\left(\dfrac{2}{3}-\dfrac{1}{4}\right)\\ \dfrac{3.3}{4.3}-\dfrac{5.2}{6.2}< \dfrac{x}{12}< 1-\left(\dfrac{2.4-1.3}{12}\right)\\ \dfrac{9-10}{12}< \dfrac{x}{12}< 1-\dfrac{5}{12}\\ -\dfrac{1}{12}< \dfrac{x}{12}< \dfrac{12-5}{12}\\ -1< x< 7\)
=> x = { 0,1,2,3,4,5,6}
34−56<x12<1−(23−14)34-56<x12<1-(23-14)
→−112<x12<1−512→-112<x12<1-512
→−112<x12<712→-112<x12<712
→−1<x<7→-1<x<7
→x∈{0;1;2;3;4;5;6}→x∈{0;1;2;3;4;5;6}
−- Vậy : x∈{0;1;2;3;4;5;6}.