(1/3)^2x-1 - (1/3)^2 = -2/27
3^7-3x = 81
3x : 9 = 391
81 : 3x + 1 = 9
(-3/4)^3x+5=(81/256)^-1
(3/5)mũ 5 . x = (3/7)mũ 7
(-1/3)mũ 3 . x = 1/81
(x - 1/2) mũ 3 = 1/27
(3x + 1)mũ 3 = -27
(x + 1/2) mũ 4 = 16/81
(4/5) mũ 5.x = (4/5) mũ 7
Tìm x
(-3/4)3x-1=256/81
Tìm x, biết:
a) \(\left(-\dfrac{1}{3}\right)^3\) .x = \(\dfrac{1}{81}\)
b) 22 . 16 >2x > 42
c) 9.27 < 3x < 243
1, Tìm x
a,3x.(2x+3)-(2x+5).(3x-2)=8
b,5x(x+2)-x.(2x-7)-3x^2=81
(\(\dfrac{-3}{4}\))3x - 1 = \(\dfrac{256}{81}\)
Có thể chia ra 2 trường hợp
Tìm x
(15x-5) (4x-1) + (3x-7) (1-16x) =81
(2x+4) (x-4) +(x-5) (x-2) =3x+5 (x-4)
(8x-3) (3x+2) - (4x+7) (x+4) = (x+1) (5x-1)
