Question

3^2x-4 -  x^0 =8

Answer 1

\(3^2\times-4-x^0=8\)

\(9\times-4-1=8\)

\(9\times-5=8\)

\(9\times=13\)

\(\Rightarrow x=\frac{13}{9}\)

Answer 2

\(3^2x-4 -x^0 = 8\)

\(9x - 4 - 1 = 8\)

\(9x - 5 = 8\)

\(9x = 8 + 5\)

\(9x = 13\)

  \(x = 13 : 9\)

\(=> x = 13 / 9\)

Answer 3

\(3^2x-4-x^0=8\)

\(\Leftrightarrow3^2x-4-1=8\)

\(\Leftrightarrow3^2x-4=8+1\)

\(\Leftrightarrow3^2x-4=9\)

\(\Leftrightarrow3^2x=9+4\)

\(\Leftrightarrow3^2x=13\)

\(\Leftrightarrow x=13:3^2\)

\(\Leftrightarrow x=13:9\)

\(\Leftrightarrow x=\frac{13}{9}\)

~ Rất vui vì giúp đc bn ~

Answer 4

3^{2x - 4} - x⁰ = 8

3^{2x - 4} - 1 = 8

3^{2x - 4} = 8 + 1

3^{2x - 4} = 9

3^{2x - 4} = 3²

2x - 4 = 2

2x = 2 + 4

2x = 6

x = 3

Answer 5

=> ko cs số thỏa mãn 

hok tốt !