Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
A=\(^{3^2.10^2-\left[13^2-\left(5^2.4+2^2.15\right)\right].10^3}\)
Bài 1: Tính. ( Nhanh nếu có thể )
a) \(25.8^3-23.8^3\)
b) \(5^4-2.5^3\)
c) \(2.4^3-4^3.7-6.4^3\)
d) \(3^2.10^3-\left[13^2-\left(5^2.4+2^2.15\right)\right].10^3\)
\(3.8.5^2+2.4^3.12+\left(2^3+3\right).6.4\)
\(600:\left\{450-\left[450-\left(2^3.5^2\right)\right]\right\}\)
Tìm x:
\(\left(x^2-1\right)^2=9\)
\(12:\left\{390:\left[5.10^2-\left(5^3+x.7^2\right)\right]\right\}=4\)
\(5^3.\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)
Giúp mik vs nha m.n!>.<
\(\frac{\left(2.4+1\frac{5}{4}\right).4.375}{\left(\frac{2}{3}-\frac{1}{6}\right)}\)- \(\frac{\left(2.75-1\frac{5}{6}\right):21}{8\frac{3}{10}-0.45}\)
\(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right)\cdot230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\) tính giúp mình với
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Tính giá trị các biểu thức sau:
a,A=\(\frac{2}{3}+\frac{5}{6}:5-\frac{1}{18}.\left(-3\right)^2\)
b,B=\(3.\left(5.\left(\left(5^2+2^3\right):11\right)-16\right)+2015\)
c,C=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
Tìm giá trị của biểu thức sau:
a)\(A=\frac{2}{3}+\frac{5}{6}:5-\frac{1}{18}.\left(-3\right)^2\)
b)\(B=3.\left\{5.\left[\left(5^2+2^3\right):11\right]-16\right\}+2015\)
c)\(C=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{2014.2016}\right)\)
