30%=0,3.Ta có
0,3xy+yx1=52
yx(0,3+1)=52
yx1,3=52
y=52/1,3
y=40
30% x y + y = 52
=> 3/10 x y + 1 x y = 52
=> y x (3/10 + 1) = 52
=> y x 13/10 = 52
=> y = 52 : 13/10
=> y = 40
30%*y+y=52
=> 3/10*y+1*y=52
=> y*(3/10+1)=52
=> y*13/10=52
y=52:13/10=40 Đs 40
\(\frac{3}{10}\) *y + y = 52
13*y=52
y=52:13
y=4
\(\frac{3}{10}\) * y =52
y =52 : \(\frac{3}{10}\)
y =40
\(\frac{13}{10}\) * y =52
y = 52 : \(\frac{13}{10}\)
y =40
\(\frac{13}{10}\) * y = 52
y = 52 : \(\frac{13}{10}\)
y = 40