Question

3 phần x+5 bằng 4 phần x-2

Answer 1

\(\dfrac{3}{x+5}=\dfrac{4}{x-2}\left(x\ne-5;x\ne2\right)\)

suy ra

`3(x-2)=4(x+5)`

`<=>3x-6=4x+20`

`<=> 3x-4x=20+6`

`<=> -x=26`

`<=> x=-26(tm)`

Answer 2

\(\dfrac{3}{x+5}=\dfrac{4}{x-2}\left(ĐKXĐ:x\ne-5;x\ne2\right)\)

\(\Leftrightarrow3\left(x-2\right)=4\left(x+5\right)\)

\(\Leftrightarrow3x-6=4x+20\)

\(\Leftrightarrow3x-4x=20+6\)

\(\Leftrightarrow-x=26\)

\(\Leftrightarrow x=-26\left(tm\right)\)