`3-(1/6-x).2/3 =2/3`
`=> (1/6-x).2/3 =3-2/3`
`=> (1/6-x).2/3 = 7/3`
`=>1/6 -x=7/3 : 2/3`
`=>1/6 - x= 7/3 . 3/2`
`=>1/6-x= 7/2`
`=>x=1/6-7/2`
`=>x=-10/3`
`3-(1/6-x). 2/3 = 2/3`
`(1/6-x). 2/3 = 3-2/3`
`(1/6-x).2/3 = 9/3 - 2/3`
`(1/6-x). 2/3 = 7/3`
`1/6-x = 7/3 : 2/3`
`1/6-x =7/3 xx 3/2`
`1/6-x = 7/2`
`x=1/6-7/2`
`x=1/6-21/6`
`x=-20/6`
`x=-10/3`
Vậy `x=-10/3`
\(3-\left(\dfrac{1}{6}-x\right)\dfrac{2}{3}=\dfrac{2}{3}\)
\(\left(\dfrac{1}{6}-x\right)\dfrac{2}{3}=3-\dfrac{2}{3}\)
\(\left(\dfrac{1}{6}-x\right)\dfrac{2}{3}=\dfrac{7}{3}\)
\(\left(\dfrac{1}{6}-x\right)=\dfrac{7}{3}:\dfrac{2}{3}\)
\(\left(\dfrac{1}{6}-x\right)=\dfrac{7}{3}.\dfrac{3}{2}\)
\(\dfrac{1}{6}-x=\dfrac{7}{2}\)
\(x=\dfrac{1}{6}-\dfrac{7}{2}\)
\(x=\dfrac{-10}{3}\)
3−(1/6−x).2/3=2/3
(1/6-x).2/3=3 - 2/3
⇒ (1/6−x).2/3=9/3-2/3
⇒ (1/6−x).2/3=7/3
⇒1/6−x=7/3:2/3
⇒1/6−x=7/3.3/2
⇒1/6−x=7/2
⇒x=1/6−7/2
⇒x=−10/3
