\(5x-4\left(6x+18-x^2-3x\right)=\left(12-8x-6x+4x^2\right)+2\)
\(\Leftrightarrow5x-4\left(-x^2+3x+18\right)=\left(4x^2-14x+12\right)+2\)
\(\Leftrightarrow4x^2-7x-72=4x^2-14x+14\Leftrightarrow7x=86\Leftrightarrow x=\dfrac{86}{7}\)
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