\(2x+2x+2x=6x\)
\(x\times\left(2+2+2\right)=6x\)
\(x\times6=6\times x\)
Vậy: \(x\in Q\)
\(2x+2x+2x=6x\)
\(x\times\left(2+2+2\right)=6x\)
\(x\times6=6\times x\)
Vậy: \(x\in Q\)
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
( x+3 ). ( X2 + 6x +9 ) -x.( 9x2 +6x +1 ) +(2x+1) . ( 4x2 -2x+1 )=28
bài 1 : tìm x
b, x(2x-5)+(4x mũ 3 - 6x mũ 2 - 6x):(-2x)=19
Thực hiện phép chia:
a) \((3x^5-9x^6+12x^9):3x\)
b) \((6x^4+4x^3+8x^2):(2x)\)
c) \((8x^6+16x^5-10x^4):(2x^4)\)
d) \((4x^4+6x^5+14x^7):(2x^3)\)
Tìm x:
a) 3x.(1 - 2x) + 6x^2 - 7x = 8.(1 - 2x) - 9
b) 2x.(1 + 3x) - 3x.(4 +2x) = 3x - 4
a,4.|3x-1|=|6x-2|+|-1,5|
b,2024.|2x-1|=2025.|1-2x|-|-2|
c,|2x+1|+|3x-1|=0
rút gọn
\(\frac{2}{2x+3}+\frac{3}{2x+1}-\frac{6x+5}{\left(2x+3\right)\left(2x-3\right)}\)
(x^2y^2 - x^2y + 4xy + 2x - 4) + (-x^2y^2 - 6x^2y - xy + 2x+4) - (2x^2y^2 - 3xy +x - 4)
=
a,2(1-6x)=(8+2x)
b,1/3-2x/5=1/10+4x/7
c,1-3x/+1=5-6x/2
câu c là tử số là 1-3x và 5-6x