2x + 2x+1 + 2x+2 + 2x+3 = 120
=> 2x ( 1 + 2 + 22 + 23) = 120
=> 2x . 15 = 120
=> 2x = 8 = 23
=> x = 3
\(2^x+2^x\cdot2^1+2^x\cdot2^2+2^x\cdot2^3=120\)
\(2^x\cdot\left(1+2+4+8\right)=120\)
\(2^x\cdot15=120\)
\(2^x=120:15\)
\(2^x=8\)
\(2^x=2^3\)
\(=>x=3\)