Question

2x2-4x+2=0

Answer 1

x=1

Answer 2

\(2x^2-4x+2=0\)

\(\Leftrightarrow2\left(x^2-2x+1\right)=0\)

\(\Leftrightarrow\left(x-1\right)^2=0\)

\(\Leftrightarrow x-1=0\)

\(\Leftrightarrow x=1\)

Vậy....

Answer 3

\(\Delta'=4-2.2=0\)vậy pt có nghiệm kép 

\(x_1=x_2=\dfrac{4}{2}=2\)