Question

2(x+1)^2 -(x-3).(x+2)=x^2 -4

 

Answer 1

\(2\left(x+1\right)^2-\left(x-3\right)\left(x+2\right)=x^2-4\)

\(\Leftrightarrow2x^2+4x+2-x^2+x+6-x^2+4=0\)

\(\Leftrightarrow5x=-12\Leftrightarrow x=-\dfrac{12}{5}\)

Answer 2

2(x + 1)² - (x - 3)(x + 2) = x² - 4

<=> 2(x² + 2x + 1) - x² - 2x + 3x + 6 = x² - 4

<=> 2x² + 4x + 2 - x² - 2x + 3x + 6 - x² + 4 = 0

<=> 2x² - x² - x² + 4x - 2x + 3x = -2 - 6 - 4

<=> 5x = -12

<=> x = \(\dfrac{-12}{5}\)