\(\left(2x-8\right)=3\\ 2x=11\\ x=\dfrac{11}{2}\)
\((2x-8)^2=9\)
\((2x-8)^2=3^2\)
\(=> 2x - 8 = 3\)
\(=> 2x=11\)
\(=>x=\dfrac{11}{2}\)
Vậy \(x=\dfrac{11}{2}\)
\(\left(2x-8\right)^2=9\)
\(\left(2x-8\right)^2=\pm\left(3\right)^2\)
\(\text{Vậy }2x-8=3\)
\(2x\) \(=8+3=11\)
\(x\) \(=11:2=\dfrac{11}{2}\)
\(\text{hoặc }2x-8=-3\)
\(2x\) \(=\left(-8\right)+3=5\)
\(x\) \(=5:2=\dfrac{5}{2}\)