\(2\left(x-7\right)^2=50\)
\(\left(x-7\right)^2=\dfrac{50}{2}=25=5^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-7=5\\x-7=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=12\\x=2\end{matrix}\right.\)
\(2.\left(x-7\right)^2=50\)
\(\left(x-7\right)^2=50:2\)
\(\left(x-7\right)^2=25\)
\(\left(x-7\right)^2=5^2=\left(-5\right)^2\)
TH1:
\(=>x-7=5\)
\(x=5+7\)
Mình làm tiếp ( do nãy bấm nhầm ):
\(...x=12\)
TH2:
\(x-7=\left(-5\right)\)
\(x=\left(-5\right)+7\)
\(x=2\)
\(#WendyDang\)
\(2\cdot\left(x-7\right)^2=50\\ \left(x-7\right)^2=25\\ x-7=\sqrt{25}\\ x-7=5\\ x=12\)
2.(x-7)^2=50
(x-7)^2=50:2
(x-7)^2=25
(x-7)^2=5^2
=>x-7=5
x=5+7
x=12
vậy x=12