(2x-7)2=16=42
suy ra 2x-7=4
or 2x-7=-4
suy ra x=11/2
or x=3/2
Th1:
2x-7=16
2x = 23
x =11,5
Th2:
2x-7 = -16
2x = -9
x= -4,5
\(\left(2x-7\right)^2=16\)
\(\Rightarrow\left(2x-7\right)^2=4^2\)(vì 16 = 42)
\(\Rightarrow2x-7=4\)
\(\Rightarrow2x=4+7\)
\(\Rightarrow2x=11\)
\(\Rightarrow x=11:2\)
\(\Rightarrow x=5,5\)
Vậy x = 5,5