\(\left(2x-3\right)^2=\dfrac{4}{9}\)
\(\left[{}\begin{matrix}2x-3=\dfrac{2}{3}\\2x-3=-\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{11}{3}\\2x=\dfrac{7}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{6}\\x=\dfrac{7}{6}\end{matrix}\right.\)