\(\Leftrightarrow\left(2x-1\right)^5\left(2x-1\right)^2-\left(2x-1\right)^5=0\\ \Leftrightarrow\left(2x-1\right)^5\left[\left(2x-1\right)^2-1\right]=0\\ \Leftrightarrow\left(2x-1\right)^5.4x\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(2x-1\right)^5=0\\4x=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=0\\x=1\end{matrix}\right.\)
Đúng 8
Bình luận (0)