đặt 2x-15=t
=>t5=t3
=>t5-t3=0
=>t3(t2-1)=0
=>t3(t-1)(t+1)=0
=>t3=0;t-1=0 hoặc t+1=0
=>t=-1;0;1
=>2x=14;15;16
=>x=7;7,5;8
vậy x=7;7,5;8
Tim x , : a)(2x-15)^5=(2x-15)^3
tim x thuộc N
\((2x-15)^3=\left(2x-15\right)^5\)
tim x
a. 2x - 13 =19
b. (2x-15)5 = (2x -15)3
Tim X
3) -12 + (2x – 9) + x= 0
4) 11 + (15 - x) = 1
5) 4 - (27 - 3) = x - (13 - 4)
6) 8 - (x - 10) = 23 - (- 4 +12)
7) 105 – 5(10 – 5x) = -20
8) (x -1)(8-2x)(3x+123) = 0
9) (x2 - 25)(x+ 10) = 0
10) x(x2+5) =
Tim x biet : 67-(15-2x)3=23×5
tim x biet
a. (x-3)(x+5)=0
b./9-2x/+x+3=2x+15
c./x+1/+/x-1/=4
tim x :-2x-40=(5-x)-(-15+60)
tim x biet 2x+5-15=0
Tim x
1/ | x+15| =7
2/ 2. | x-5| =8
3/ 3. |2x-7|= 9
