Ta có: \(121=11^2\)
\(\Rightarrow\left(2x-1\right)^2=11^2\)
\(\Rightarrow2x-1=11\)
\(\Rightarrow2x=11+1=12\)
\(\Rightarrow x=12:2=6\)
Vậy x = 6
(2x - 1)2 = 121
=> (2x - 1)2 = 112
=> 2x - 1 = 11
=> 2x = 12
=> x = 6
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Vì 11^2=121
=> 2x-1=11
=> 2x=11+1
=>2x=12
=>x=12:2
x=6
(2x-1)^2=121
(2x-1)^2=11^2
2x-1=11
2x=12
x=6
(2x-1)2=112
=>2x-1=11
2x =11+1
2x=12
x=6
Bạn nhớ tích ch0 mình nha !
(2x-1)^2=121
(2x-1)^2=11^2
=)2x-1=11
2x=11+1
2x=12
x=12:2
x=6
(2x - 1)2 = 121
=> \(\orbr{\begin{cases}2x-1=11\\2x-1=-11\end{cases}}\)=> \(\orbr{\begin{cases}2x=12\\2x=-10\end{cases}}\)=> \(\orbr{\begin{cases}x=6\\x=-5\end{cases}}\)
(2x - 1)^2 + 121
=> (2x - 1)^2 = 11^2
=> 2x - 1 = 11
=> 2x = 11 + 1
=> 2x = 12
=> x = 12 : 2 = 6
Ta thấy 11^2 = 121
=> 2x - 1 = 11
=> 2x = 12
=> x = 6