Ta có tổng trên là:
2 + 8 = 10
Đáp số : 10.
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cho \(\frac{x^2+y^2}{x^2-y^2}+\frac{x^2-y^2}{x^2+y^2}=a\) . Tính \(\frac{x^8+y^8}{x^8-y^8}+\frac{x^8-y^8}{x^8+y^8}\)theo a
cho số thực a,b thỏa mãn \(a^2\ne b^2\)đặt \(M=\frac{a^2+b^2}{a^2-b^2}+\frac{a^2-b^2}{a^2+b^2}\)tính \(N=\frac{a^8+b^8}{a^8-b^8}+\frac{a^8-b^8}{a^8+b^8}\)theo M
cho a,b ,c deu duong .cmr
\(\frac{8}{\left(a+b\right)^2+4abc}+\frac{8}{\left(b+c\right)^2+4abc}+\frac{8}{\left(a+c\right)^2+4abc}+a^2+b^2+c^2\ge\frac{8}{a+3}+\frac{8}{b+3}+\frac{8}{c+3}\)
cho số thực a,b,c>0. CMR
\(\frac{8}{\left(a+b\right)^2+4abc}+\frac{8}{\left(b+c\right)^2+4abc}+\frac{8}{\left(c+a\right)^2+4abc}+a^2+b^2+c^2\ge\frac{8}{a+3}+\frac{8}{b+3}+\frac{8}{c+3}\)
1+2+3+4+5+6+7+8+9-1-2-3-4-5-6-7-8-9*1*2*3*4*5*6*7*8*9:1:2:3:4:5:6:7:8:9=???
rút gọn hộ mik vs
4)\(\sqrt{8+2\sqrt{15}}\) -\(\sqrt{8-2\sqrt{15}}\)
5)\(\sqrt{5+2\sqrt{6}}\) +\(\sqrt{8-2\sqrt{15}}\)
cho x,y,z là số thực ,\(xyz=2\sqrt{2}\)
Tìm GTNN của \(P=\frac{x^8+y^8}{x^4+y^4+x^2y^2}+\frac{x^8+z^8}{x^4+z^4+x^2z^2}+\frac{y^8+z^8}{y^4+z^4+y^2z^2}\)
(2√2 + 8)^(x - 1) >= (2√2 - 8)^(3 - x^2)
Pleft(xright)sqrt[3]{sqrt{x+8}left(x^4+8x^3+12xright)+6x^3+48x^2+8}đặt Asqrt{x+8}left(x^4+8x^3+12xright)+6x^3+48x^2+8 sqrt{x+8}left(x^4+8x^3right)+6x^2left(x+8right)+12xsqrt{x+8}+8 sqrt{left(x+8right)^3}x^3+3sqrt{left(x+8right)^2}x^22+3sqrt{left(x+8right)}x4+8 left(xsqrt{x+8}+2right)^3Rightarrow Pleft(xright)xsqrt{x+8}+2
Đọc tiếp
\(P\left(x\right)=\sqrt[3]{\sqrt{x+8}\left(x^4+8x^3+12x\right)+6x^3+48x^2+8}\)
đặt \(A=\sqrt{x+8}\left(x^4+8x^3+12x\right)+6x^3+48x^2+8\)
\(=\sqrt{x+8}\left(x^4+8x^3\right)+6x^2\left(x+8\right)+12x\sqrt{x+8}+8\)
\(=\sqrt{\left(x+8\right)^3}x^3+3\sqrt{\left(x+8\right)^2}x^22+3\sqrt{\left(x+8\right)}x4+8\)
\(=\left(x\sqrt{x+8}+2\right)^3\)
\(\Rightarrow P\left(x\right)=x\sqrt{x+8}+2\)
DK
26 tháng 8 2023 lúc 8:46
Căn 2 + Căn 8 + Căn 52 = 8 căn 2