27 ( 13 - 16 ) - 16( 13 - 27)
= 27 x 13 - 27 x 16 - 16 x 13 + 16 x 27
= 27 x 13 - 16 x 13 = 13 x ( 27 - 16 ) = 13 x 11 = 143
k đúng cho mình nha
=27*13-27*16-16*13+16*27=13*(27-16)+(16*27-27*16)=13*11+0=143.
k nha có j kb vs mk
Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
27 ( 13 - 16 ) - 16( 13 - 27)
= 27 x 13 - 27 x 16 - 16 x 13 + 16 x 27
= 27 x 13 - 16 x 13 = 13 x ( 27 - 16 ) = 13 x 11 = 143
k đúng cho mình nha
=27*13-27*16-16*13+16*27=13*(27-16)+(16*27-27*16)=13*11+0=143.
k nha có j kb vs mk
bài 3 thực hiện phép tính
a\(\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{4}{18}+\dfrac{20}{-17}+\dfrac{-2}{9}+\dfrac{21}{56}\)
b\(\left(\dfrac{9}{16}+\dfrac{8}{-27}\right)+\left(1+\dfrac{7}{16}+\dfrac{-19}{27}\right)\)
c\(\left(\dfrac{13}{5}+\dfrac{7}{16}\right)+\left(\dfrac{-15}{16}+\dfrac{6}{15}\right)\) d \(\left(6-2\dfrac{4}{5}\right).3\dfrac{1}{8}-1\dfrac{3}{5}:\dfrac{1}{4}\)
Tính hợp lý:
\(A=1+\frac{-9}{16}.\frac{13}{27}+\frac{9}{16}.\frac{-14}{27}\)
\(B=\frac{7}{18}.\left(\frac{-12}{23}-\frac{4}{15}\right)+\frac{7}{18}.\left(\frac{8}{30}+\frac{35}{23}\right)\)
Làm đầy đủ các bước nha
1,Tính : ( Hãy tính nhanh nếu có thể )
a,\(\frac{3^6.45^4-15^{13}.\left(\frac{1}{5}\right)^9}{27^4.25^3+45^6}\)
b,\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\)
B=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
C=\(\frac{2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)
D=\(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
Tính:
A = $5\frac{3}{7}+\left(-5,35\right)+\frac{1}{3}+\left(-2,41\right)+\frac{3}{21}+\left(-1,24\right)$537 +(−5,35)+13 +(−2,41)+321 +(−1,24)
B = $4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}$42516 +25.(916 −11764 ):278
Trình bày cách giải và đáp án giúp mình nha! ^^
Tính
1, \(\left(\frac{-4}{3}\right)^3.\left(\frac{-27}{20}\right)^4\)
2, \(\left(\frac{-13}{8}\right)^3.\left(\frac{-32}{13}\right)^4\)
Tính tích A\(=\left(1+\frac{5}{7}\right)+\left(1+\frac{5}{16}\right)+\left(1+\frac{5}{27}\right).....\left(1+\frac{5}{1840}\right)\)
\(\frac{9^2.8^6}{16^4.3^{13}}+\frac{\left(3^2\right)^2.\left(2^3\right)^6}{\left(2^4\right)^4.3^{13}}=?\)
\(\dfrac{\left(3x4x2^{16}\right)}{11x2^{13}x4^{11}-16^9}\)