\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.3^6}{3^5.2^5.2^6}=\frac{2^7.3^6}{3^5.2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)
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\(^{2\hept{\begin{cases}\\\end{cases}}\hept{\begin{cases}\\\\\end{cases}}\orbr{\begin{cases}\\\end{cases}}\frac{ }{ }_{ }_{ }\widebat{ }}\)